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Re: New work on running biomech by Hutchinson
On Friday, September 10, 2004, at 10:47 AM, Jordan Mallon wrote:
From: Amtoine Grant <ajgrant@eastlink.ca>
I'm not keen on exactly what a Froude or MOR number is, so basically
what I'd like to know is why would it be multiplied by 3.6 for the
adult Tyrannosaur?
Well, Dr. Holtz already explained what the Froude number was (Fr =
v^2/gh) in a previous post. MOR simply refers to a specimen at the
Museum of the Rockies, in this case, a _T. rex_ specimen. And 3.6 is
simply a conversion factor used to go from m/s to km/h:
m/s x 1km/1000m x 3600s/1h = 3.6
Okay. I've just skimmed through this discussion and I don't think the
actual m/s figure has been mentioned for T-Rex, just a mention of
Froude 17(I think). So what were the m/s figures for Coelophysis,
Compsognathus, Dilophosaurus, Allosaurus, Velociraptor & Archaeopteryx?